Want to read an async AJAX request in FireBug console?

AJAX=new XMLHttpRequest();AJAX.open( 'POST', 'www.YourUrl.com', true );AJAX.send( 'postKey=postVal' );AJAX.onreadystatechange = function(){ console.log( AJAX ); }

This prints everything, not just a successful response. Very useful for learning about the XMLHttpRequest object and reading POST responses inside an authenticated session without any cross-domain trickery.